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8 HCl (aq) + 2 KMnO4 (aq) → Cl2 (g) + 2 KCl (aq) + 4 H2O2 (aq) + 2 MnCl2 (aq)

8 HCl (aq) + 2 KMnO4 (aq) Cl2 (g) + 2 KCl (aq) + 4 H2O2 (aq) + 2 MnCl2 (aq)

This is an oxidation-reduction (redox) reaction:

2 MnVII + 10 e 2 MnII (reduction)

2 Cl-I 2 e 2 Cl0 (oxidation)

8 O-II 8 e 8 O-I (oxidation)

KMnO4 is an oxidizing agent, HCl is a reducing agent, KMnO4 is a reducing agent.