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2 HCl (aq) + 2 KMnO4 (aq) + 3 K2SO3 (aq) → H2O (l) + 3 K2SO4 (aq) + 2 KCl (aq) + 2 MnO2 (s)

Home/ Chemical Reactions-Equations / 2 HCl (aq) + 2 KMnO4 (aq) + 3 K2SO3 (aq) → H2O (l) + 3 K2SO4 (aq) + 2 KCl (aq) + 2 MnO2 (s)

2 HCl (aq) + 2 KMnO4 (aq) + 3 K2SO3 (aq) → H2O (l) + 3 K2SO4 (aq) + 2 KCl (aq) + 2 MnO2 (s)

2 HCl (aq) + 2 KMnO₄ (aq) + 3 K₂SO₃ (aq) → H₂O (l) + 3 K₂SO₄ (aq) + 2 KCl (aq) + 2 MnO₂ (s)

This is an oxidation-reduction (redox) reaction:

2 Mn^VII + 6 e^– → 2 Mn^IV (reduction)

3 S^IV – 6 e^– → 3 S^VI (oxidation)

KMnO₄ is an oxidizing agent, K₂SO₃ is a reducing agent.

This is a precipitation reaction: MnO₂ is the formed precipitate.