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18 HCl (aq) + 6 KMnO4 (aq) + 5 CH3OH (aq) → 19 H2O (l) + 5 CO2 (g) + 6 KCl (aq) + 6 MnCl2 (aq)

Home/ Chemical Reactions-Equations / 18 HCl (aq) + 6 KMnO4 (aq) + 5 CH3OH (aq) → 19 H2O (l) + 5 CO2 (g) + 6 KCl (aq) + 6 MnCl2 (aq)

18 HCl (aq) + 6 KMnO4 (aq) + 5 CH3OH (aq) → 19 H2O (l) + 5 CO2 (g) + 6 KCl (aq) + 6 MnCl2 (aq)

18 HCl (aq) + 6 KMnO4 (aq) + 5 CH3OH (aq) → 19 H2O (l) + 5 CO2 (g) + 6 KCl (aq) + 6 MnCl2 (aq)

This is an oxidation-reduction (redox) reaction:

6 MnVII + 30 e– → 6 MnII (reduction)

5 C-II – 30 e– → 5 CIV (oxidation)

KMnO4 is an oxidizing agent, CH3OH is a reducing agent.

This is a gas evolution reaction, CO2 is the formed gas.