14 HCl + KMnO4 + 3 SnCl2 → 4 H2O + KCl + MnCl + 3 H2SnCl6
14 HCl + KMnO4 + 3 SnCl2 → 4 H2O + KCl + MnCl + 3 H2SnCl6
This is an oxidation-reduction (redox) reaction:
MnVII + 6 e– → MnI (reduction)
3 SnII – 6 e– → 3 SnIV (oxidation)
KMnO4 is an oxidizing agent, SnCl2 is a reducing agent.